-0.936y^2-0.0512y+0.01024=0

Solution for -0.936y^2-0.0512y+0.01024=0 equation:

-0.936y^2-0.0512y+0.01024=0

a = -0.936; b = -0.0512; c = +0.01024;
Δ = b2-4ac
Δ = -0.05122-4·(-0.936)·0.01024
Δ = 0.04096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.0512)-\sqrt{0.04096}}{2*-0.936}=\frac{0.0512-\sqrt{0.04096}}{-1.872}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.0512)+\sqrt{0.04096}}{2*-0.936}=\frac{0.0512+\sqrt{0.04096}}{-1.872}
$